Solve Balloon Problem Homework: Time & Speed Impact

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To solve the balloon problem, the relevant equation is Xf = Xo + Vo(T) - 1/2(g)(T)², where Xf is the final position, Xo is the initial height, Vo is the initial velocity, and g is the acceleration due to gravity. The initial height is 80 m, the initial velocity is 12 m/s, and g is -9.8 m/s². Rearranging the equation leads to a quadratic form: 0 = -4.9T² + 12T + 80. The quadratic formula can then be applied to solve for time (T), ensuring that the positive solution is chosen. This method will yield the time it takes for the package to reach the ground and its impact speed.
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Homework Statement


Question: A hot-air balloon is ascending at the rate of 12m/s and is 80m above the ground when a package is dropped over the side.
a.)How long does the package take to reach the ground? b.)With what speed does it hit the ground?

Homework Equations


I know -- acceleration = -9.8 Initial velocity = 12 m/s and initial height = 80 m.

I know I have to use this formula
Xf = Vo + 1/2 (g) (T)2

Vo = 12 m/s
Xf = 80 m
g = -9.8 m/s2

I set Xf to 0.How would I find Time?

Thanks
 
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CrossFit415 said:
I know I have to use this formula
Xf = Vo + 1/2 (g) (T)2
I think you mean:
Xf = Xo + Vo(T) - 1/2 (g) (T)2
where g = 9.8 m/s2
How would I find Time?
Time is the only unknown in the above quadratic equation, so solve for T.
 
How would I go on about doing that? I can't seem to get T by itself in this equation.
 
Doc Al said:
I think you mean:
Xf = Xo + Vo(T) - 1/2 (g) (T)2
where g = 9.8 m/s2

Time is the only unknown in the above quadratic equation, so solve for T.

That user is correct by the way because this is the form you should get. Well, since the object starts 80 m above the ground, x_0 = 80 obviously.

Here is the equation you get:

x_f = 80 + 12t - 4.9t²

CrossFit415 said:
How would I go on about doing that? I can't seem to get T by itself in this equation.

It's not impossible to find t. To find t, use the quadratic equation as that user indicates. That is the way to find t. Remember that:

at² + bt + c = 0 OR c + bt + at² = 0

t = (-b ± √(b² - 4ac))/(2a)

OR

t = (-b + √(b² - 4ac))/(2a) or t = (-b - √(b² - 4ac))/(2a)

By letting the corresponding values be the a, b, c variables and then, solving for t, you should get the answer (it must be positive!).
 
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