Solve Calc 2 Integral 0 to h: 1/((h-r)^2+r^2))

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SUMMARY

The integral from 0 to h of the function 1/((h-r)^2 + r^2) dr can be approached using techniques such as partial fractions or trigonometric substitution. The denominator simplifies to 2(r^2 - rh) + h^2, which can be rewritten by completing the square to yield 2(r - A)^2 + B^2. The antiderivative of this expression is K * arctan(something) + C, where K, A, and B are constants determined during the simplification process.

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Homework Statement


this integral owned me, can anyone tell me what to do to solve it/ how to solve it or a step by step solution. from 0 to h, 1/((h-r)^2+r^2))dr


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The Attempt at a Solution


Im thinking partial factions or trig sub...
 
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Let's look at the denominator.
(h - r)^2 + r^2 = h^2 - 2hr + r^2 + r^2
= 2r^2 - 2hr + h^2
= 2(r^2 - rh) + h^2

Now, complete the square in the first expression to get
2(r - A)^2 + B^2 (you'll have to figure out A and B)

The antiderivative of the expression above is K * arctan(something) + C.

Enough of a hint?
 

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