Solve Electrical Potential Homework: 24 kV, Droplet Mass 2.2 x 10^-13 kg

[NZS92]

Homework Statement

A potential difference of 24 kV maintains a downward-directed electric field between two horizontal parallel plates separated by 1.8 cm. Find the charge on an oil droplet of mass 2.2 x 10^-13 kg that remains stationary in the field between the plates.

Homework Equations

PE=KE
qV=(1/2)mv^2

V=Ed

E=k(q/r^2)

The Attempt at a Solution

PE=KE
qV=(1/2)mv^2
q=((1/2)mv^2)/V

If velocity is zero, then "q" is zero. Since its stationary. (I think the only way to find velocity is PE=KE)
I'm stucked at here, any solutions?

 

[Doc Al]

Consider the forces acting on the droplet.