Solve Energy Needed to Raise 2000kg Lift to 10m

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To raise a 2000kg lift to a height of 10m, the gravitational potential energy required is calculated as EP = mgh, resulting in 196,000 J. Given the engine's efficiency of 60%, the energy output (EOUT) is determined by multiplying the total energy by the efficiency factor, yielding 117,600 J. The discussion confirms that the calculations align with the principles of energy output and input related to efficiency. The user is on the right track with their approach. The conversation emphasizes the importance of understanding energy efficiency in mechanical systems.
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Homework Statement



A engine used to raise a lift is 60% efficient, and the lift's mass is 2000kg. How much energy would be needed to raise it to 10m?

Homework Equations



Efficiency = energy output/ energy input *100

The Attempt at a Solution



EP=mgh = 2000*9.8*10= 196000 J.

Therefore, eff. = energy output/energy input *100 = (0.6=EOUT/196000

EOUT= 0.6*196000=117600 J

Am I on the right track?
 
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Hi kabton14, welcome to PF.
Here Eout = mgh.
 

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