Solve for Bmax: Quick Faraday Equation with Transformer Parameters

Thread starter kishanpatel50
Start date Apr 24, 2009
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Faraday

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The discussion centers on calculating Bmax using the Faraday equation with given transformer parameters. The equation Bmax = (V1)/(4N1fA) is applied, where V1 is specified as 10V, and the peak-to-peak voltage is noted as 20V. Participants clarify that for the calculation, the peak voltage (10V) should be used rather than the peak-to-peak or Vrms values. The derived Bpeak is calculated to be 0.104 Tesla using the provided values. The focus remains on ensuring the correct voltage value is used in the Faraday equation for accurate results.

Apr 24, 2009

kishanpatel50

I have this equation and the following values for a transformer

B_max= (V₁)/(4N₁fA)

V₁=10v, i.e. 20v peak-to-peak
N₁=40 turns
f=5000Hz
A=76x10^-6 m²

When i substitute in the voltage, do i use the 10v, or the peak to peak, or would i have to convert to V_rms

Last edited: Apr 24, 2009

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Apr 24, 2009

Bob S

the Faraday equation is

V_peak= (2 pi f) B_peak A N

So B_peak= 10/(6.28 f A N) = 0.104 Tesla

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