Solve for mass of a second object in a momentum question

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In a head-on collision problem, two objects stick together post-collision, and the goal is to find the mass of the second object. The initial mass of the first object is 120 kg, moving at 12 m/s north, while the second object is unknown and moving at 18 m/s south. The final velocity after the collision is 4.0 m/s south. The initial attempt to solve the momentum equation resulted in an incorrect mass of 68.6 kg due to sign errors in the velocity directions. Correcting the signs by designating north as positive led to the accurate solution of 140 kg for the second object's mass.
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Homework Statement


Two objects collide head-on, and are stuck together after collision. Find mass of second object.
Givens:
m1 = 120 kg
v1 = 12 m/s(N)
m2 = ?
v2 =18 m/s (S)
v' = 4.0 m/s (S)

Homework Equations


m1v1 + m2v2 = m1v1' + m2v2'
v'= (m1v1 + m2v2) / (m1+m2)

The Attempt at a Solution


-inelastic collision
-combined mass after collision
-therefore, final velocity will be the same
-I'm not sure on how to rearrange the equation so only one m2 is present in the equation

v'= (m1v1 + m2v2) / (m1+m2)
(4) = ((120)(12) + m2(18)) / (120 + m2)
4(120 + m2) = 1440 + m2(18)
480 + 4m2 = 1440 + m2(18)
480 - 1440 = 18m2 - 4m2
-960 = 14m2
m2 = 68.6 kg

The actual answer is supposed to be 140 kg.

(sorry if this looks confusing, I'm new to this website and haven't quite figured it out yet.)
Thanks
 
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You need to be careful with signs. Each velocity quoted has a stated direction, N or S. Pick whether N or S should be the positive direction and express the velocities accordingly.
 
haruspex said:
You need to be careful with signs. Each velocity quoted has a stated direction, N or S. Pick whether N or S should be the positive direction and express the velocities accordingly.
Oh right, okay.
When I make N positive and S negative and solve it, I get around the right answer.

Thank You!
 
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