Solve for Point Corresponding to P=(-2,4) on g(x) Using f(x) and g(x)=2f(x-1)-3

  • Thread starter Thread starter Skydog287
  • Start date Start date
AI Thread Summary
To find the point on the graph of g(x) corresponding to P=(-2,4), first recognize that f(-2)=4 since P is on the graph of y=f(x). The function g(x) is defined as g(x)=2f(x-1)-3, indicating that it scales and shifts the graph of f(x). To determine the corresponding point on g(x), substitute x with -1 (since g(x) uses x-1) to find g(-1). This results in g(-1)=2f(-2)-3, which simplifies to g(-1)=2(4)-3=5, yielding the point (-1,5) on the graph of g(x).
Skydog287
Messages
1
Reaction score
0
How do i solve this? :confused: The question says: Given that the point P=(-2,4) is on the graph of y=f(x) and g(x)=2f(x-1)-3; find the point on the graph of g(x) corresponding to the point P.

Thanks in advance,
Sky
 
Physics news on Phys.org
Hint: Another way of saying that the point P (-2,4) is on the graph of y = f(x) is to say:

f(-2) = 4

g(x) scales and shifts the graph of f(x)
 
What, exactly, is meant by "the point on the graph of g(x) corresponding to the point P"?
 

Thread 'Family of lines that are at a distance of 5 from the origin'

I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
View full post »

Similar threads

Understanding the graphical effect of f(x+a)
Replies
19
Views
2K
Prove that ## g(x)=f(x)\log {x}-\int_{2}^{x}t^{-1}f(t)dt ##.
Replies
7
Views
1K
Is there a rule that states that I should not divide in this scenario?
Replies
10
Views
1K
Find integer points on this equation
Replies
8
Views
1K
Is ##f(x)=2^{x}-1## considered an exponential function?
Replies
12
Views
2K
Find the range of the function ##f(x) = \frac{e^{2x}-e^x+1} {e^{2x}+e^x+1}##
Replies
8
Views
3K
Am I understanding horizontal shift properly?
Replies
3
Views
2K
F(x)=(x+1)^0.5, h(x)=x^2+3, what is the range of f(h(x))?
Replies
4
Views
1K
Derivative of a piecewise function
Replies
6
Views
2K
Transforming Functions: Solving g(x) = 2f(-x+(3/2))
Replies
4
Views
2K

Hot Threads

Recent Insights

Back
Top