Solve for Req with T to Delta Transform

  • Thread starter Thread starter zr95
  • Start date Start date
  • Tags Tags
    Delta Transform
AI Thread Summary
The discussion revolves around finding the equivalent resistance (Req) in a circuit using both direct calculations and a T to Delta transformation. The initial calculation yielded a correct Req of 32.5 ohms without redrawing the circuit. However, when attempting to apply the T to Delta transformation, the participant encountered discrepancies in their calculations, particularly overlooking the 25-ohm resistor. The confusion stems from misapplying the transformation rules and not accounting for all resistors in the circuit, leading to incorrect results. Properly accounting for all components is crucial for accurate transformations and calculations.
zr95
Messages
25
Reaction score
1

Homework Statement


Find Req in the given circuit
upload_2016-9-26_13-10-23.png


Homework Equations


Series: req = r1+r2...
parallel: 1/req = 1/r1 + 1/r2 ...

The Attempt at a Solution


Without redrawing the circuit I do:
12||60 = 10
10+20 = 30
30 || 30 = 15
15+10 = 25
25||25 = 12.5
12.5+15+5 = 32.5 = Req
This is the correct answer.

upload_2016-9-26_13-10-3.png

However if I redrew the T to a delta I no longer can get the right answer.
108 || 0 = 0
(36 || 30) || (180 || 10) = 6
6||25...
and so on

Where am I going wrong in my logic? Am I not allowed to do this sort of transformation on this problem?
 

Attachments

  • upload_2016-9-26_13-9-38.png
    upload_2016-9-26_13-9-38.png
    76.5 KB · Views: 499
Physics news on Phys.org
zr95 said:
(36 || 30) || (180 || 10) = 6

Why is the 180 in parallel with the 10?
 
I completely looked over the 25 ohm resistor when I did that. Thanks.
 

Similar threads

Replies
14
Views
5K
Replies
18
Views
3K
Replies
46
Views
10K
Replies
7
Views
3K
Replies
5
Views
3K
Replies
5
Views
2K
Back
Top