GeorgeK
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Dear All,
The bivariate Poisson distribution is as follows,
<br /> \[ f(y_{s},y_{t})=e^{-(\theta_{s} + \theta_{t}+\theta_{st})}\frac{\theta_{s}^{y_{s}}}{y_{s}!}\frac{\theta_{t}^{y_{t}}}{y_{t}!}<br /> \sum_{k=0}^{min(y_{s},y_{t})} \binom{y_{s}}{k} \binom{y_{t}}{k} k!\left(\frac{\theta_{st}}{\theta_{s} \theta_{t}}\right)^k.\]<br />
Given that f(y_{s},y_{t}) >= 0, solve for \theta_{st}.
Many thanks in advance,
George
The bivariate Poisson distribution is as follows,
<br /> \[ f(y_{s},y_{t})=e^{-(\theta_{s} + \theta_{t}+\theta_{st})}\frac{\theta_{s}^{y_{s}}}{y_{s}!}\frac{\theta_{t}^{y_{t}}}{y_{t}!}<br /> \sum_{k=0}^{min(y_{s},y_{t})} \binom{y_{s}}{k} \binom{y_{t}}{k} k!\left(\frac{\theta_{st}}{\theta_{s} \theta_{t}}\right)^k.\]<br />
Given that f(y_{s},y_{t}) >= 0, solve for \theta_{st}.
Many thanks in advance,
George
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