Solve Free-Fall Problem: A Ball Dropped from Rest

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The discussion centers on solving a physics problem involving a ball dropped from rest, which covers three-quarters of the distance to the ground in the last second of its fall. Participants suggest using kinematic equations to express total height in terms of time and to calculate the distance fallen in the last second. They emphasize that the problem can be approached without needing to find the ball's velocity at any point, relying instead on a single kinematic equation. Despite efforts to manipulate various formulas, the original poster expresses frustration at not making progress. The conversation encourages collaborative problem-solving and applying fundamental physics principles.
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I've spent about an hour and a half on this question, working with different formulas and manipulating equations but I still can't figure it out. The question:

"A ball, dropped from rest, covers three-quarters of the distance to the ground in the last second of its fall. From what height was the ball dropped, and what was the total time of the fall?"

I would type here what I have figured out, but really it seems like I have gotten nowhere. I think I've come close, though.
 
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Why don't you tell us what your thinking is on the problem and give some indication of what you have tried.
 
ny_batteri4536 said:
I've spent about an hour and a half on this question, working with different formulas and manipulating equations but I still can't figure it out. The question:

"A ball, dropped from rest, covers three-quarters of the distance to the ground in the last second of its fall. From what height was the ball dropped, and what was the total time of the fall?"

I would type here what I have figured out, but really it seems like I have gotten nowhere. I think I've come close, though.

Work out the expression for total height in terms of total time.

Then work out how much distance is fallen in t-1. That will give you another expression for h. Can you take it from there?

AM
 
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Convert what you said into an equatiom, think about distance=rate*time, and you will need to use that from free-fall the velocity of the ball at any time t is v=at, where a=9.8 m/s^2.
 
Wishbone said:
Convert what you said into an equatiom, think about distance=rate*time, and you will need to use that from free-fall the velocity of the ball at any time t is v=at, where a=9.8 m/s^2.

It is not nesscary to find the velocity at any point during the free fall. The problem can be solved with the application of a single kinematic equation.
 
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