Solve Gold Ring Resistivity Question, Practical Difficulties

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Homework Help Overview

The discussion revolves around a resistivity problem involving a gold ring used as a resistor in a circuit. The specifics include measurements of voltage and current, as well as the dimensions of the ring's diameter and cross-section.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore calculating the resistance of the ring and its halves, considering the formula for resistance in parallel. Some question the practical difficulties of the experiment, particularly regarding the cross-section of the gold ring.

Discussion Status

There is ongoing exploration of the calculations needed to determine resistivity, with some participants expressing confusion and seeking assistance. Multiple interpretations of the problem and its solution are evident, particularly regarding the expected answer.

Contextual Notes

Participants note practical difficulties related to the idealized assumptions of the ring's geometry and material properties, as well as discrepancies in expected answers from reference materials.

TheOne123
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I was doing some questions from a book on resistivity and I came across this, I really can't work this out, I'm stumped.

In a resistance experiment, a gold ring as connected into a circuit as a resistor. The connections touched on a diametrically opposite points on the circular ring. Its diameter is 2CM, and the metal's cross-section is a rectangle 3mm by 0.5mm. A volt meter is connected across the ring measured 8.3 m V, whilst the current though it was measured at 18 A.

a) Calculate the resistivity of gold.
b) Describe a practical difficulty with undertaking an experiment of this kind.
 
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You can consider two half-rings connected in parallel. For each one use the formula for the resistance of a wire.
 
TheOne123 said:
I was doing some questions from a book on resistivity and I came across this, I really can't work this out, I'm stumped.
Calculate the resistance of the ring in this circuit. Then work out the resistance of one half of the ring on the basis that the two halves of the ring amount to two half rings in parallel. Then work out the resistivity from that resistance.

AM
 
Hmm ok. I'm still a bit cofused. Can someone start. Of te calculation for me please an I will go from there. Thanks in advance.
 
As for practical difficulties, how many gold rings have you seen that have a perfectly rectangular cross-section?
 
TheOne123 said:
Hmm ok. I'm still a bit cofused. Can someone start. Of te calculation for me please an I will go from there. Thanks in advance.

Use Ohm's law to determine the resistance.

Since this total resistance is from two sides of the ring in parallel, you can work out the resistance of each side of the ring:

[tex]\frac{1}{R} = \frac{1}{R_{half}} + \frac{1}{R_{half}}[/tex]

Use [itex]\rho L/A = R[/itex] to find the resistivity, where L is the length of the conductor and A is the cross sectional area.

AM
 
Ahh I still keep getting it wrong.

The answer should be 4.4 X 10-7 as it says in the back.
 
TheOne123 said:
Ahh I still keep getting it wrong.

The answer should be 4.4 X 10-7 as it says in the back.

Isn't 4.4 X 10-8?
This is more realistic.
 
nasu said:
Isn't 4.4 X 10-8?
This is more realistic.

It says 4.4 X 10-7. How did you get 4.4 X 10-7?
 
  • #10
If you show your work I'll try to identify the mistake.
But I think you'll get about 4x10^(-8).
 

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