Solve Harmonic Problem: Find Bullet Speed Before Impact

  • Thread starter Thread starter ceeforcynthia
  • Start date Start date
  • Tags Tags
    Harmonic
AI Thread Summary
To solve the problem of finding the bullet's speed before impact, the conservation of momentum principle is essential. The user calculated the combined mass of the bullet and block as 0.625 kg and used the formula V = A√(k/m) to find the velocity after impact, resulting in 22.26 m/s. However, they are struggling to relate this back to the bullet's initial speed. The correct approach involves applying the conservation of momentum equation, which states that the momentum before impact equals the momentum after impact. The final goal is to determine that the bullet's speed before impact is 557 m/s.
ceeforcynthia
Messages
11
Reaction score
0
Hi! I've been working on this problem for a while, subtracting this and that.. but i can't get the answer which is 557m/s. Help would be greatly appreciated! Thanks in advance ><

1. A 25.0g bullet strikes a .600kg block attached to a fixed horizontal spring whose spring constant is 6.70x10^3 and sets it into vibration with an amplitude of 21.5cm. What is the speed of the bullet before impact if the two objects move together after impact?


2. V=A\sqrt{k/m}



3. I used the equation above, adding the masses together (.625kg). I got the velocity to be 22.26m/s... but now i can't figure out how to get the speed of the bullet.
 
Physics news on Phys.org
conservation of momentum
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Help with a Simple Harmonic Motion problem
Replies
1
Views
4K
Springs, Simple Harmonic Motion
Replies
1
Views
3K
Simple harmonic motion: mass on a spring is hit by a bullet
Replies
6
Views
6K
What was the initial temperature of the lead bullet before it melted completely?
Replies
3
Views
1K
Collisions in a harmonic oscillator
Replies
18
Views
3K
Simple harmonic motion problem.
Replies
4
Views
2K
Thermodynamics, bullet melting ice problem
Replies
4
Views
2K
Simple harmonic motion - answer slightly off
Replies
2
Views
2K
Speed of bullet and kinetic energy lost in the impact
Replies
22
Views
7K
What Is the Speed of the Bullet?
Replies
20
Views
15K

Hot Threads

Recent Insights

Back
Top