Solve Hydrostatics Problem & Draw FBD

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The discussion revolves around solving a hydrostatics problem and accurately drawing the Free Body Diagram (FBD). The user has calculated reaction forces for water and mud but struggles with achieving equilibrium at joints A, B, C, and D in their FBD. They note that the vertical compression force at joint D does not account for a horizontal component, leading to equilibrium issues. Suggestions from others emphasize the need to consider fixed supports at A and D to handle lateral forces. The user seeks further clarification on how to correctly represent these forces in the FBD.
AngelofMusic
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Hello,

I'm currently trying to solve a problem involving hydrostatics, but I'm getting stuck when it comes to drawing the forces in the FBD.

The original problem is here:

http://img.villagephotos.com/p/2003-11/466966/hydrostatics.jpg

This is my attempt at drawing the FBD:

http://img.villagephotos.com/p/2003-11/466966/fbd.jpg

My calculations:

R(water) = 187.3 kN
R(mud) = 644.7 kN

I think that should be correct.

However, once I isolated the joint at the intersection of A,B, and C, there is no way I can get the joint to be in equilibrium. (See the bottom right corner of my FBD).

The same problem occurs at D, where the compression force in member D only goes up vertically, but I also have a horizontal component to the reaction force at D.

What am I doing wrong? Does anyone have any hints/suggestions on how to solve this?

Thanks a lot!
 
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However, once I isolated the joint at the intersection of A,B, and C, there is no way I can get the joint to be in equilibrium. (See the bottom right corner of my FBD).
You will need to assume that A and D are set in at their base (not hinged) so that they can support sideways forces.
 
Okay, so would the FBDs look something like this, then?

http://img.villagephotos.com/p/2003-11/466966/fbd2.jpg
 
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