darkchild
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Homework Statement
\int_{-3}^{1}\frac{x}{\sqrt{9-x^{2}}}
Homework Equations
Let f be continuous on the half-open interval (a, b] and suppose that
\lim_{x \to a^{+}} |f(x)| = \infty. Then
\int_{a}^{b}f(x) dx = \lim_{ t \to a^{+}}\int_{t}^{b}f(x)<br /> dx
The Attempt at a Solution
\int_{-3}^{1}\frac{x}{\sqrt{9-x^{2}}}<br /> <br /> = \lim_{ t \to -3^{+}}\int_{t}^{1}\frac{x}{\sqrt{9-x^{2}}}<br /> <br />
u = 9 - x^{2}
du = -2x dx
\lim_{ t \to -3^{+}}\int_{t}^{1}\frac{x}{\sqrt{9-x^{2}}}<br /> <br /> = \lim_{ t \to 0^{+}}-\frac{1}{2}\int_{t}^{8} u^{-1/2} du <br /> <br /> =\lim_{ t \to 0^{+}}-u^{1/2}|_{t}^{8}<br /> <br /> =-\sqrt{3sin(1)} + \lim_{ t \to -3^{+}}\sqrt{3sin(t)}<br /> <br /> =-1.588840129 + ?
I get 0 for the limit, but according to Maple and my graphing calculator, that does not give the correct value for this integral. The correct value is approximately -2.8. May I please have some guidance as to what may have went wrong?