Solve Impulse Experienced by 70kg Person Jumping 5m

  • Thread starter Thread starter phintastic
  • Start date Start date
  • Tags Tags
    Impulse
AI Thread Summary
To calculate the impulse experienced by a 70kg person landing after a 5m jump, the impulse equation I = Δp = FΔt should be used, where I represents impulse and p denotes momentum. Impulse is defined as the change in momentum, which occurs when the person lands and comes to a stop. The momentum can be calculated using the person's mass and velocity just before landing. The necessary steps involve determining the velocity upon impact and applying the impulse formula. Understanding these concepts is crucial for solving the problem effectively.
phintastic
Messages
7
Reaction score
0
im reviewing for my final tomorrow, and there is a question that asks for the impulse experienced if a 70kg person lands on firm ground and stops after jumping from a height of 5m. what equation should i use to solve this?
 
Physics news on Phys.org
phintastic said:
im reviewing for my final tomorrow, and there is a question that asks for the impulse experienced if a 70kg person lands on firm ground and stops after jumping from a height of 5m. what equation should i use to solve this?
Start with writing down the equation for impulse. Impulse= ?
 
i don't know the equation for impulse, that's my main problem :P
 
<br /> I = \Delta p = F\Delta t<br />

Where I is impulse, and p is momentum.

So impulse is a change in momentum, or the product of a force and the time period over which it acts.
 
Last edited:
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

Is the Impulse of Force Calculated Correctly in This Bullet and Block Collision?
Replies
25
Views
3K
Impulse and perfectly inelastic collision between 2 points
Replies
4
Views
784
Solving Impulse on Jumper for 50 kg Woman
Replies
9
Views
2K
Momentum and impulse of jump problem
Replies
11
Views
4K
Collisions, Impulses and Impulsive Tension
Replies
17
Views
4K
Horizontal impulse on a ball at rest on a plane (with friction)
Replies
14
Views
3K
Rolling with slipping and combined momentums
Replies
14
Views
1K
Pushing a stalled car out of an intersection
Replies
1
Views
2K
Impulse on and the distance traveled by a cannonball
Replies
2
Views
2K
Acceleration vs Time Bungee Graph
Replies
1
Views
5K

Hot Threads

Recent Insights

Back
Top