Can You Solve This Complex Differential Equation?

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A complex differential equation is presented for discussion, specifically y''' = y with the solution y(t) = a*exp(b*t) where b^3 = 1. The general solution is expressed as y(x) = c1*exp(q1*x) + c2*exp(q2*x) + c3*exp(q3*x), with constants c1, c2, and c3 determined by initial conditions. The values for q1, q2, and q3 are provided, with q1 being 1 and the others involving complex numbers. The solution can also be reformulated in real terms as y(x) = exp(x)*c1 + A*exp(-x/2)*cos(sqrt(3)*x + B), where A and B are constants derived from c2 and c3. The thread encourages participants to engage by posting their own problems.
Ben-CS
I have decided to post an exercise and see what happens. You can post your own problems, too, if you wish. Have fun with this one!


Solve the following differential equation:

y′′′ = y
 
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y(t) = a*exp(b*t) where b^3 = 1.
 
The general solution is of the form

y(x)=c1*exp(q1*x)+c2*exp(q2*x)+c3*exp(q3*x)

where c1, c2 and c3 are (complex) constant that can be fixed by initial conditions and
q1=1
q2=(-1+i*sqrt(3))/2
q3=(-1-i*sqrt(3))/2

This can be re-written in the real field as

y(x)=exp(x)* c1 + A*exp(-x/2)*cos(sqrt(3)*x+B) )

where A and B are new constants depending on c2 and c3 only.
 
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