Solve IVP DE: x'=-3x+4y-2, y'=-2x+3y, x(o)=-1, y(o)=3

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Thanks for the help.

Homework Statement



Solve the IVP: x'=-3x+4y-2, y'=-2x+3y, x(o)=-1, y(o)=3


The Attempt at a Solution


x''=-3x'+4y'
x''=-3x+4(-2x+3y)=-3x-8x+12y
y=(x'+3x+2)/4
x''=-3x-8x+12((x'+3x+2)/4)
x''-x=6
xgeneral=xh+xp
Xg=Ce^t+Ce^-t-6
Yg=1/4(Ce^t-Ce^-t+3Ce^t+3Ce^t)
Yg=Ce^t+1/2(Ce^-t)-4
x(t)=
y(t)=
 
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there's an error in your first line, where you've replaced x' with x

why not write in matrix form and solve as a system of linear equations
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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