Solve Kinematics Problem: y = y0 + Vot + 1/2gt²

AI Thread Summary
The discussion revolves around solving a kinematics problem using the equation y = y0 + Vot + 1/2gt². The user attempts to find when the height of a ball equals that of a rock, noting that the ball is thrown one second later. They initially misassign a negative sign to the velocity term, leading to an incorrect solution. Clarifications highlight that the signs depend on the chosen coordinate system, where upward motion is positive and gravitational acceleration is negative. Understanding the relationship between velocity and acceleration signs is crucial for accurate problem-solving in kinematics.
James_22
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Homework Statement


upload_2016-2-16_19-44-18.png


Homework Equations


y = y0 + Vot + 1/2gt²

The Attempt at a Solution


We have to know when yball = y rock
for the ball : t = t-1 because it's throwed 1 sec later the rock.
we have to fine when yball = yrock :

12.t - 0.5*9.8*t² = 18*(t-1) - 0.5*9.81*(t-1)²..I find the answer with this equation.. t = 1.45 y=7.43
but my first equation was : -12.t - 0.5*9.8*t² = 18*(t-1) - 0.5*9.81*(t-1)²
I put the sign (-) before 12t because I thought when acceleration and velocity have the same direction they have the same sign but when I do that, I don't find the good answer. If someone can explain me that..
Thank you
 
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The signs associated with values depends upon your choice of coordinate system.

Generally you choose your coordinate system before assigning signs to things accordingly. In this case if you chose your coordinates so that upwards is positive, then an upward velocity is positive. Gravitational acceleration is always downwards, so that's why it gets the negative sign.
 
James_22 said:

Homework Statement


View attachment 95959

Homework Equations


y = y0 + Vot + 1/2gt²

The Attempt at a Solution


We have to know when yball = y rock
for the ball : t = t-1 because it's throwed 1 sec later the rock.
we have to fine when yball = yrock :

12.t - 0.5*9.8*t² = 18*(t-1) - 0.5*9.81*(t-1)²..I find the answer with this equation.. t = 1.45 y=7.43
but my first equation was : -12.t - 0.5*9.8*t² = 18*(t-1) - 0.5*9.81*(t-1)²
I put the sign (-) before 12t because I thought when acceleration and velocity have the same direction they have the same sign but when I do that, I don't find the good answer. If someone can explain me that..
Thank you
When you throw something upward, its initial velocity is going to be reduced by the gravitational attraction of the Earth on it, so the velocity term and the acceleration term will have opposite signs. After the object has reached its highest point above the ground and starts to fall back to earth, its velocity is increased by the same gravitational attraction, so the velocity term and the acceleration term will have the same sign.
 
James_22 said:
but my first equation was : -12.t - 0.5*9.8*t² = 18*(t-1) - 0.5*9.81*(t-1)²
I put the sign (-) before 12t because I thought when acceleration and velocity have the same direction they have the same sign
Ok, but what made you think they have the same direction here?
 
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