Solve Kirchhoff's Law: Find I1, I2 & I3

  • Thread starter Thread starter sammblehh
  • Start date Start date
  • Tags Tags
    Law
AI Thread Summary
To solve for currents I1, I2, and I3 using Kirchhoff's laws, apply Kirchhoff's Current Law (KCL) which states that the sum of currents entering a junction equals the sum leaving, represented as I1 - I2 - I3 = 0. Additionally, use Kirchhoff's Voltage Law (KVL) which states that the sum of the electrical potential differences (voltage) around any closed network is zero, expressed as Vab + Vbc + Vcd + Vda = 0. The known values of voltage and resistance for the three resistors can be used to derive the equations needed to find the currents. By substituting the values into these equations, the currents can be calculated. Understanding and applying these laws is essential for solving circuit problems effectively.
sammblehh
Messages
2
Reaction score
0
Hi There,

Im trying to revise for a test and I need help with the following question

I need to find I1 I2 and I3,

I only know the voltage and resistance of the 3 resistors

I have drawn the circuit and attached it,

so stuck! please help!
 

Attachments

  • 1797414_223596261181714_6746465809025867123_n.jpg
    1797414_223596261181714_6746465809025867123_n.jpg
    39 KB · Views: 486
Physics news on Phys.org
So, what are the equations you get from Kirchoff's current law and voltage law?
 
i1 - i2 - i3 = 0

and

Vab + Vbc + Vcd + Vda = 0

I think
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top