Solve Laplace Transform: te^t*H(t-1)

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Homework Help Overview

The discussion revolves around the Laplace transform of the function te^t multiplied by the Heaviside step function H(t-1). Participants are exploring the application of Laplace transform properties and integration techniques in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to apply known Laplace transform equations and properties, questioning how to combine individual transforms. There is a focus on the integration method and the role of the Heaviside function in the transformation process.

Discussion Status

The discussion is ongoing, with participants providing feedback on each other's attempts and clarifying misunderstandings about the application of Laplace transforms and integration. Some guidance has been offered regarding the foundational definitions of the Laplace transform.

Contextual Notes

There are indications of confusion regarding the correct formulation of the Laplace transform of H(t-1) and the integration process. Participants express varying levels of confidence in their understanding of the integral method and its application to this problem.

nobodyuknow
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Homework Statement



Laplace transform: te^t*H(t-1)

Homework Equations



L{te^t} = 1/(s-1)^2
L{H(t-1)} = e-s/s

The Attempt at a Solution



Using e^(at)f(t) -> F(s-a)
with..e^(1t)H(t-1)
We can get, e^(-1s-1)/(s-1) = e^(-s-1)/(s-1) [I think?]
Thus applying tf(t) -> -dF/ds
Derive[e^(-s-1)/(s-1)] w.r.t. s, you get:
-se^(-s-1)/(s-1)^2

Which is close, but, not exact.

I know the answer is se^s-1/(s-1)^2

But how do they come to that?
I don't think the order of my working would affect the final outcome.

All help appreciated
 
Last edited:
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You need to show some attempt at solving the problem on your own.
 
nobodyuknow said:

Homework Statement



Laplace transform: te^t*H(t-1)

Homework Equations



L{te^t} = 1/(s-1)^2
L{H(t-1)} = e-s/s

The Attempt at a Solution



I know the answer is se^s-1/(s-1)^2

But how do they come to that?

How do you combine the two individual laplace transforms to calculate the final?

No. L{H(t-1)} is not e-s/s = e-1; it is e^(-s)/s. You must learn to use parentheses when writing things in plain text.

If I were doing the problem I would not bother trying to combine LTs using some "rules"; I would just write out the actual integration and go on from there.
 
Thanks, that was a mistake sorry

So basically use the integration rule and integrate te^t and then apply the Heaviside function?
I'm sorry, I'm not too confident with the Integral method, but..

integral{te^t} = (t-1)e^(t-st)

I'm not sure how to work from there.

[Googling Heaviside Integration as of now]
 
nobodyuknow said:
Thanks, that was a mistake sorry

So basically use the integration rule and integrate te^t and then apply the Heaviside function?
I'm sorry, I'm not too confident with the Integral method, but..

integral{te^t} = (t-1)e^(t-st)

I'm not sure how to work from there.

[Googling Heaviside Integration as of now]

What do you mean by the "integral method"? What do you think the Laplace transform of f(t) actually IS? Go back and look at the basic definitions---it is, by definition, an integral of a certain type. All the so-called "rules" you want to use are just properties of integrals, applied to some special cases.

And no, you do NOT do the integral and then apply the Heaviside function; the Heaviside function is part of the definition of f(t) in this case, and comes before any integrations.

It is not at all clear to me that you really understand what you are doing; that is why I suggest you go right back to square one and start with basic definitions.
 

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