Solve Lens Equations: Object 8cm @ 80cm, Focal Length 25cm

Thread starter loopsnhoops
Start date May 30, 2011
Tags

Lens

AI Thread Summary

To solve the lens equation for an object 8 cm high placed 80 cm in front of a converging lens with a focal length of 25 cm, the lens formula (1/f = 1/do + 1/di) is essential. The object distance (do) is 80 cm, and the focal length (f) is 25 cm, allowing for the calculation of the image distance (di). After determining di, the magnification formula (height of image = magnification × height of object) can be used to find the image height. The discussion emphasizes the importance of applying these formulas correctly to arrive at the solution. The final calculations yield both the image position and height based on the provided parameters.

May 30, 2011

loopsnhoops

Hi, I need someone to outline how to get the solution of the problem which is:

An object 8.0 cm high is placed 80 cm in front of a converging lens of focal length 25 cm. Calculate the image position and height.

Thanks, Eric

Physics news on Phys.org

May 31, 2011

tiny-tim

Science Advisor

Homework Helper

Welcome to PF!

Hi Eric! Welcome to PF!

What formulas do you know that might be relevant here?

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...

View full post »

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

View full post »

Thread 'Explain this asphalt sheen'

This problem is two parts. The first is to determine what effects are being provided by each of the elements - 1) the window panes; 2) the asphalt surface. My answer to that is The second part of the problem is exactly why you get this affect. And one more spoiler:

View full post »