Solve pH of NaOH + Acetic Acid Mixture

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The discussion centers on calculating the pH of a mixture of NaOH and acetic acid after specific volumes and concentrations are combined. The reaction between acetic acid and sodium hydroxide occurs in a 1:1 mole ratio, leading to the presence of unreacted acetic acid in the solution. Participants highlight that the resulting mixture may function as a buffer solution, allowing for the use of the pK value to determine pH without extensive calculations. Understanding the equilibrium of weak acids and bases is emphasized as crucial for solving such problems. Overall, the conversation underscores the importance of recognizing the chemical species and their concentrations in the solution.
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Homework Statement



What is the pH after 12.50 mL of 0.10 M NaOH has been added to 25.00 mL of 0.10 M acetic acid?


Homework Equations





The Attempt at a Solution


i have no idea how to do this.
 
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The concentration of each starting solution is the same. Acetic acid and sodium hydroxide react in a 1:1 mole ratio. One of those will be in excess when the quantities of solutions are mixed. Which one, and what concentration will it be?
 
Once you know what buffer is, and once you realize what is molar ratio of both reactants, you don't need any calculations to find out the answer.


&
 
Borek said:
Once you know what buffer is, and once you realize what is molar ratio of both reactants, you don't need any calculations to find out the answer.

Borek
--
pH calculator & buffer calculator

The exact truth would be a little different from that. Note that the solution will have unreacted acetic acid. 37.50 ml. of entire solution containing 0.0125*0.10 moles of unneutralized acetic acid. The salt present should likely not have much effect on pH. I'm assuming that there is enough acid present to overcome any effect of the salt, but I can't be sure unless I actually perform the analytical calculation-------- wait! Maybe this really IS a buffer solution, being half the moles are the salt and half the moles are the acetic acid. There is a simple way to find pH of this buffer using pK value, right?
 
symbolipoint said:
Maybe this really IS a buffer solution, being half the moles are the salt and half the moles are the acetic acid. There is a simple way to find pH of this buffer using pK value, right?

Bingo :smile: Hopefully rmarsino will get to this point as well.
 
In post #5, I began writing using only half my mind. The concept caught up with me as I wrote and figured. rmarsino, when you study equilibrium of weak acids and weak bases, you will learn about buffers. You will also learn how to find pH of solutions containing weak bases, weak acids, and weak acids or bases and salts of these.

I actually learned this stuff best when I was NOT enrolled in a course to learn it; but while I was reviewing on my own. For monoprotic or monofunctional compounds, this stuff is full of details, but not necessarily difficult. Learning it well takes time, patience, and much exercise and repetition.
 
These things are always done the same way from three-and-a-half principles, stated in

https://www.physicsforums.com/showpost.php?p=1754973&postcount=3

You say you have no idea how to do. In general start by writing all the chemical species present. Then write what you know about their concentrations...

It is true that in this particular case there is a (instructive) shortcut as pointed out by symbolipoint.
 

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