Solve Physics Duck Problem: Find Min V0 & Angle for Bullet Targeting Duck

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The discussion centers around calculating the minimum initial velocity (V0) and angle (a) required for a bullet to hit a duck flying horizontally at height h with velocity v. The user initially applies kinematic equations but encounters discrepancies with the book's answer, which suggests V0min = sqrt(v^2 + 0.5gh) instead of their derived V0min = sqrt(v^2 + 2gh). The conversation highlights the importance of using conservation of energy principles, leading to a clearer understanding that the bullet needs sufficient kinetic energy to match the duck's speed while considering vertical motion. The user concludes that the problem can also be approached through kinematics, emphasizing the need for precise calculations. Ultimately, the discussion illustrates the complexities involved in solving projectile motion problems in physics.
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1. A duck flies horizontally with velocity v at a height h. When a duckhunter is right below it, he shoots with his shotgun. What is the minimum initial velocity V0 of the bullet and the angle a at which he shoots so that the bullet hits the duck?
Obviously, given are v, h and gravity acceleration g.

2.I think I just need to take that
Xduck = vt,
Xbullet = V0xt,
Ybullet = V0yt - 1/2 gt2,
Vy = V0y - gt for the bullet.

3.I just took
Xduck = Xbullet,
Yduck = Ybullet,
and Vy > 0 for the bullet
but I still get a result different than the one in my book.
 
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All the things you have written are correct, assuming you are using h as the Y value for duck and bullet. Unless you use the Pythagorean Theorem for v0x and v0y then you're stuck with 2 equations and 3 unknowns (the 3rd unknown being the angle a).
 
Yeah, I took Yduck = h.

My final result is that V0min = sqrt(v2 + 2gh) but the book says the answer is V0min = sqrt(v2 + 0.5gh)
 
Well, I don't know why your answer is different by that factor, but I do know that this is more easily solved using conservation of energy. Since it asks for the minimum speed, you can assume the bullet's vertical velocity is zero when it hits the duck, so it need only have enough kinetic energy to be moving at the same speed as the duck:

\frac{1}{2}mv02 = mgh + \frac{1}{2}mv2

and the correct answer for the speed comes pretty easily from that.

You can do the same thing with kinematics, I suppose, and make Vfy = 0
 
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