Solve Polyprotic pH Problem: K2HPO4 & H3PO4 (65 Chars)

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To solve the polyprotic pH problem involving K2HPO4 and H3PO4, the initial concentration of K2HPO4 is 0.05 M in 800 mL of water, and the target pH is 7. The mass balance equation for H3PO4 includes contributions from various phosphate species, while the charge balance involves potassium and hydrogen ions. At pH 7, the presence of H3PO4 and PO43- can be ignored, simplifying the calculations. The Henderson-Hasselbalch equation and stoichiometry are suggested as effective methods for determining the volume of H3PO4 needed to achieve the desired pH. Understanding these balances is crucial for accurately solving the problem.
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A .05 M sample of K2HPO4 was dissolved in 800 mL of water, and the pH was adjusted to 7 by using a 1 M solution of H3PO4 followed by water bringing the volume up to 1 L. How many mL of H3PO4 were added? (On this problem charge and mass balance have to be used.)

My problem is just in the very beginning, as my book is terrible, I am not entirely sure on how to approach this problem.

Im assuming the mass balance for H3PO4 will be:

[H3PO4] + [H2PO4- ] + [HPO42-] + [PO43-] = 1 M

And the charge balance for K2HPO4 would be:

[H+] + [K+] = [OH-] + [H2PO4-] + 2*[HPO42-] + 3*[PO43-]


I'm really uncertain whether I'm missing anything or what the next step should be.
 
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Please try these lectures on pH calcualtion as a starting point.

At pH 7.0 you can ignore presence of H3PO4 and PO43-. I have a gut feeling that this question can be solved just using Henderson-Hasselbalch equation and stoichiometry.

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