Solve Redox Titration Problem w/ NaNO2 & KMnO4 - Help Needed!

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Discussion Overview

The discussion revolves around a redox titration problem involving potassium permanganate (KMnO4) and sodium nitrite (NaNO2). Participants are seeking assistance in calculating the molar concentration of sodium nitrate produced in the reaction, with a focus on stoichiometric relationships and the balancing of the chemical equation.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant expresses difficulty with the problem and requests help with the titration involving KMnO4 and NaNO2.
  • Another participant suggests starting with a balanced equation and calculating the number of moles of permanganate used to find the stoichiometric amount of sodium nitrate.
  • A participant indicates confusion about how to determine the stoichiometric amount of sodium nitrate and what to divide by 0.02L to find the concentration.
  • Another reply advises looking at stoichiometric calculations and emphasizes using moles rather than mass to find the molar concentration.

Areas of Agreement / Disagreement

There is no consensus on the specific steps to solve the problem, as participants express varying levels of understanding and clarity regarding stoichiometric calculations and the balancing of the equation.

Contextual Notes

Participants have not provided a balanced chemical equation, and there is uncertainty regarding the stoichiometric coefficients involved in the reaction.

Kail
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I have many problesm with this question. Can someone help me please?

In a titration of patasium permanganate soloution with acidified sodium nitrate solution

MnO4- + BO2- H+ -----> Mn+2 + NO3- +H2O

45 ml of 0.05M of KMnO4 reacts complitely with 20.0 mL of NaNO2 solution.

Calculate the molat concentration of sodium nitrate.

Please give me a hand with this. I relly need help to pass my chimetry curse.
 
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You must start with balanced equation. Once it is balanced calculate number of moles permanganate used and stoichiometric amount of sodium nitrate. Latter divided by 0.02L will give you concentration.
 
Sorry but I kinda dontt understand how to get the stoichiometric amount of sodium nitrate. And what do I have to divide by 0.02L. Sorry it's just I kinda not that good at chemestry.
 
Last edited:

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