Solve Silent Ringing Bell Homework Statement

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The discussion revolves around calculating the length of a clapper rod needed for a bell to ring silently, meaning the oscillation periods of both the bell and clapper must match. The initial calculations provided a period of 1.784 seconds for the bell, leading to a clapper length of 4.96 meters, which was later identified as incorrect due to arithmetic errors. Participants clarified that the goal is to mismatch the frequencies of the bell and clapper for a silent ring, suggesting that the clapper must be in a vacuum to achieve this. The correct approach involves ensuring the final equation incorporates the squared term for 2π. Ultimately, the conversation highlights the importance of precise calculations and understanding the physical principles behind the problem.
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Homework Statement


A large bell is hung from a wooden beam so it can swing back and forth with negligible friction. The center of mass of the bell is 0.65m below the pivot, the bell has mass 37.0 Kg, and the moment of inertia of the bell about an axis at the pivot is 19.0 kg*m^2. The clapper is a small, 1.8 kg mass attached to one end of a slender rod that has length L and negligible mass. The other end of the rod is attached to the inside of the bell so it can swing freely about the same axis as the bell.

a)What should be the length of the clapper rod for the bell to ring silently-that is, for the period of oscillation for the bell to equal that for the clapper?


Homework Equations


Tbell=2pisqrt(I/mgd)

The Attempt at a Solution


okay so we have to have Tbell=TClapper
Tbell=2pisqrt(I/mgd)=2pisqrt(19/37*9.8*0.65)=1.784 s
1.784=TClapper=2pisqrt(I/mgd)
(1.748^2*g)/2pi=L=4.96m

Now I still have the wrong answer with this method, could someone please help me determine waht I'm doing wrong, as always any help is appreciated.
 
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anubis01 said:
(1.748^2*g)/2pi=L=4.96m
Shouldn't that 2∏ be squared?
 
Doc Al said:
Shouldn't that 2∏ be squared?
yes it should, sigh I really need to improve my arithmitic skills. Thanks for the help.
 
Doc Al said:
Shouldn't that 2∏ be squared?

What about the 1.8kg ?
 
A large bell is hung from a wooden beam so it can swing back and forth with negligible friction. The center of mass of the bell is 0.45 below the pivot, the bell has mass 40.0 , and the moment of inertia of the bell about an axis at the pivot is 20.0 . The clapper is a small, 1.8 mass attached to one end of a slender rod that has length and negligible mass. The other end of the rod is attached to the inside of the bell so it can swing freely about the same axis as the bell.
What should be the length of the clapper rod for the bell to ring silently-that is, for the period of oscillation for the bell to equal that for the clapper?

Im getting 2.2 meters !? Can someone solve!
 
It's a trick question. You are solving for the bell to "swing" silently not "ring" silently. The answer (to the actual question) is that you have to mismatch the clapper and bell frequencies to ensure a hit (or it can't ring) and then it has to be in vacuum so it can ring silently.
 
using the above work I got 1.1m, You should also remember to have (2pi)2 instead of just 2pi in the final part of the equation. It would also be helpful if you were to post your work.
 
anubis01 said:
using the above work I got 1.1m, You should also remember to have (2pi)2 instead of just 2pi in the final part of the equation. It would also be helpful if you were to post your work.

Sight at me.. Cheers man.
 

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