Solve sin(t) cos(2t)=b1 sin(t)+b2 sin(2t)+b3 sin(3t)

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sin(t) cos(2t) = ??

ok so i have to find the values for b1,b2 and b3...but i am clueless on how to find them
can anyone help?

sin(t) cos(2t) = b1 sin(t) + b2 sin(2t) + b3 sin(3t):

i thought of converting it to complex but that did not help much!
 
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o yeah..forgot about those! thanks guys!
 

Thread 'Prove that the integral is equal to ##\pi^2/8##'

Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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