Solve T4(x) for Taylor Polynomials of f(x)=arctan(11x)

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Homework Statement



Find T4(x), the Taylor polynomial of degree 4 of the function f(x)=arctan(11x) about x=0.
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Homework Equations



The taylor polynomial equation

Tn(x)= f(x)+(fn(x)(x-a)^n)/n!...

The Attempt at a Solution



When I take every derivative of f(x)=arctan(11x) I always end up with an x in the numerator, so when i plug in 0 for x my derivative ends up with 0, so theoretically the answer would just be arctan(11x) which is wrong.

This is what I am getting for my first few derivatives

F'(x)=22x/(11x^2+1)
F''(x)=-484x^2/(11x^2+1)^-2

what am i doing wrong?
 
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Those are all wrong.
F'(x)=11/(121x^2+1)
only the odd derivatives will vanish
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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