MHB Solve the following equations for a

  • Thread starter Thread starter lmae
  • Start date Start date
Click For Summary
The discussion focuses on solving two algebraic equations for the variable a. For the first equation, 15/a = -10, the solution is found to be a = -3/2 after rearranging and simplifying. The second equation, (a + 5)/4 + (a - 6)/3 = 1/6, requires multiplying by the least common multiple to simplify, ultimately leading to the solution a = 11/7 after distributing and combining like terms. The participants confirm the steps and clarify the process, ensuring understanding of the algebra involved. Overall, the thread provides clear solutions and guidance for solving these equations.
lmae
Messages
8
Reaction score
0
Hi folks,

Need some help on the following equations. I have never been great with maths, algebra especially, and am struggling to understand.Solve the following equation for a:
Q1: 15/a=-10

Q2: Solve for a in the equation: a+5/4+a-6/3=1/6

Any help is greatly appreciated.
 
Mathematics news on Phys.org
Hi lmae and welcome to MHB! :D

Q1:

15/a = -10

Multiply through by a:

15 = -10a

Rearrange and simplify:

a = -15/10 = -3/2

Make sense?

Q2: Solve for a in the equation: (a + 5)/4 + (a - 6)/3 = 1/6

Multiply through by the least common multiple of 4 and 3, which is 12:

3(a + 5) + 4(a - 6) = 2

O.k? Can you continue?
 
Hi,

Thanks very much for the help. The first now makes total sense to me and was able to complete a whole bunch correctly, so a big thanks!

The second one I am still struggling with. Is that the final answer there? Or should I be doing more working out to get to another answer?
 
3(a + 5) + 4(a - 6) = 2

Distribute:

3 * a + 3 * 5 + 4 * a - 4 * 6 = 2

3a + 15 + 4a - 24 = 2

Combine like terms:

3a + 4a + 15 - 24 = 2

7a - 9 = 2

7a = 2 + 9

7a = 11

a = 11/7
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 10 ·
Replies
10
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K