Solve The Laws of Motion: Tension in a Bird on a Wire

AI Thread Summary
The discussion focuses on solving a physics problem involving a bird on a wire between two telephone poles. The scenario describes a 1.00-kg bird causing the wire to sag 0.200 m, with the distance between poles being 50.0 m. Participants emphasize the importance of drawing a free-body diagram to analyze the forces acting on the bird and the wire. The tension produced in the wire is determined by recognizing that the vertical components of the tensions must equal the weight of the bird, which is 9.8 N. The conversation concludes with guidance on calculating the tension by considering the horizontal and vertical components of the forces.
physics=world
Messages
109
Reaction score
0
1. The distance between two telephone poles is 50.0 m. When
a 1.00-kg bird lands on the telephone wire midway between
the poles, the wire sags 0.200 m. (a) Draw a free-body diagram
of the bird. (b) How much tension does the bird produce
in the wire? Ignore the weight of the wire.2. this problem was from the laws of motion section. dealing with tension and f=ma
3. i need help with beginning the problem. any suggestions.so i drew the free body diagram. so would t1 = t2 make the tension the same for both sides? and i found the weight of the bird which is 9.8 N. so where do i go from here to find the tension?
 
Last edited:
Physics news on Phys.org
You have enough information to make a sketch of the situation--do that first. Since it is a massless wire, assume initially that the unloaded wire is perfectly straight with no initial tension.
 
After you draw the FBD, the weight of the bird would cause the wire to drop a bit and create an angle from the original horizontal position.

Yes, the tensions are exactly the same. But you first need to find the horizontal and vertical components of the tensions (you only have to do this once because the tensions are the same).

In the vertical direction, you know that the bird is exerting a force downwards equal to 9.8N, and so the tensions of the wires must add together to exert a force upwards equal to 9.8N. Because there are two separate tensions, each tension has a vertical component of 4.9N.

See how far you can get with this.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top