Solve the second-order differential equation

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Homework Help Overview

The discussion revolves around solving a second-order differential equation. Participants are examining the correctness of a proposed solution and its derivatives, as well as the substitution into the original equation.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the process of verifying a solution by calculating derivatives and substituting them back into the original equation. There are questions regarding the correctness of specific terms and integration steps.

Discussion Status

Some participants are actively checking the validity of the proposed solution and derivatives, while others are seeking clarification on specific mistakes identified in the integration process. There is an ongoing exploration of the correctness of the solution without a clear consensus yet.

Contextual Notes

There are indications of potential errors in integration and the formulation of the solution, which are being questioned by participants. The discussion reflects a collaborative effort to identify and rectify these issues.

Fatima Hasan
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Homework Statement


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Homework Equations



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The Attempt at a Solution


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Can someone check my answer please ?
 

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Hi Fatima:

I suggest you take your solution
y(x) = x2 - (1/3)x-1
and calculate y'(x) and y"(x).
Then substitute these three functions of x into corresponding terms of the original equation. After the substitution, the resulting equation should be reducible to
0 = 0​
if your and answer is correct.

Regards,
Buzz
 
Buzz Bloom said:
the resulting equation should be reducible to
0 = 0
I didn't get this equation , can you tell me where is my mistake please ?
 
Fatima Hasan said:
I didn't get this equation , can you tell me where is my mistake please ?
Your answer for ##y_2(x)## in the next-to-last line in post #1 is incorrect. Check the integration that you did.
 
Mark44 said:
Your answer for ##y_2(x)## in the next-to-last line in post #1 is incorrect. Check the integration that you did.
##y_2(x) = x(x-\frac{1}{x})##
##y_2(x) = x^2-1##
##y(x) = C_1 y_1(x) + C_2y_2(x)##
##y(x) = C1 x + C_2 (x^2-1)##
 
Fatima Hasan said:
##y_2(x) = x(x-\frac{1}{x})##
##y_2(x) = x^2-1##
##y(x) = C_1 y_1(x) + C_2y_2(x)##
##y(x) = C1 x + C_2 (x^2-1)##
OK, now can you check that your solution is correct?
 
Mark44 said:
OK, now can you check that your solution is correct?
Got it , thank you.
 

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