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I didn't get this equation , can you tell me where is my mistake please ?Buzz Bloom said:the resulting equation should be reducible to
0 = 0
Your answer for ##y_2(x)## in the next-to-last line in post #1 is incorrect. Check the integration that you did.Fatima Hasan said:I didn't get this equation , can you tell me where is my mistake please ?
##y_2(x) = x(x-\frac{1}{x})##Mark44 said:Your answer for ##y_2(x)## in the next-to-last line in post #1 is incorrect. Check the integration that you did.
OK, now can you check that your solution is correct?Fatima Hasan said:##y_2(x) = x(x-\frac{1}{x})##
##y_2(x) = x^2-1##
##y(x) = C_1 y_1(x) + C_2y_2(x)##
##y(x) = C1 x + C_2 (x^2-1)##
Got it , thank you.Mark44 said:OK, now can you check that your solution is correct?
A second-order differential equation is a mathematical equation that involves the second derivative of a function. It is commonly used to describe the behavior of physical systems in various fields, such as physics, engineering, and economics.
There are various methods for solving a second-order differential equation, including separation of variables, substitution, and using the method of undetermined coefficients. The method used depends on the form of the equation and the initial conditions given.
The general solution to a second-order differential equation is the most general form of the solution that satisfies the equation. It typically contains two arbitrary constants, which can be determined by applying the initial conditions.
The initial conditions in a second-order differential equation refer to the values of the function and its first derivative at a specific point. These conditions are used to find the particular solution that satisfies the equation.
Yes, a second-order differential equation can have multiple solutions. This is because the general solution contains two arbitrary constants, which can take on different values depending on the initial conditions. However, the particular solution determined by the initial conditions is unique.