Mar 11, 2009 #1 mike79 Messages 9 Reaction score 0 Hi everybody, can anyone help me in finding the analytic solution of the trascendental equation in the attached file? A1, alfa1, alfa2, a and b are constants. is it possible to solve it by means of Mathematica? thanks Michele Attachments equation.doc equation.doc 16.5 KB · Views: 192
Hi everybody, can anyone help me in finding the analytic solution of the trascendental equation in the attached file? A1, alfa1, alfa2, a and b are constants. is it possible to solve it by means of Mathematica? thanks Michele
Mar 11, 2009 #3 mike79 Messages 9 Reaction score 0 A1*(tan(xa/alfa2)/tan(xa/alfa1))-tan(xa/alfa2)*tan(xb/alfa2)-A1*(tan(xb/alfa2)/tan(xa/alfa1))=1 thanks again
A1*(tan(xa/alfa2)/tan(xa/alfa1))-tan(xa/alfa2)*tan(xb/alfa2)-A1*(tan(xb/alfa2)/tan(xa/alfa1))=1 thanks again
Mar 11, 2009 #4 qntty Messages 289 Reaction score 4 Here's the equation in tex \frac{A_1 \cdot \tan{ax / \alpha_2}}{\tan{ax / \alpha_1}} - \tan{ax / \alpha_2} \cdot \tan{bx / \alpha_2} - \frac{A_1 \cdot \tan{bx / \alpha_2}}{\tan{\ax / \alpha_1}} = 1 Last edited: Mar 12, 2009
Here's the equation in tex \frac{A_1 \cdot \tan{ax / \alpha_2}}{\tan{ax / \alpha_1}} - \tan{ax / \alpha_2} \cdot \tan{bx / \alpha_2} - \frac{A_1 \cdot \tan{bx / \alpha_2}}{\tan{\ax / \alpha_1}} = 1
Mar 12, 2009 #5 HallsofIvy Science Advisor Homework Helper Messages 42,895 Reaction score 984 That appears to be a single equation in two different variables, xa and xb. It will not have a single solution.
That appears to be a single equation in two different variables, xa and xb. It will not have a single solution.
Mar 12, 2009 #6 mike79 Messages 9 Reaction score 0 x is the only variable. a and b are real constants. you have to read x*a and x*b and not xa and xb
Mar 12, 2009 #7 csprof2000 Messages 286 Reaction score 0 So what you really have is A*tan(a'x)/tan(b'x) - tan(a'x)*tan(c'x) - A*tan(c'x)/tan(b'x) = 1 For appropriate choices of a', b', and c'.
So what you really have is A*tan(a'x)/tan(b'x) - tan(a'x)*tan(c'x) - A*tan(c'x)/tan(b'x) = 1 For appropriate choices of a', b', and c'.