Solve Tricky Commutator: Heisenberg Picture, a_k(t)

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Homework Statement



Part of a much larger problem dealing with the Heisenberg picture. I am not remembering how to start evaluating the following commutator:

\left [ a_k(t),\left(\sum_{k,\ell}a_k^\dagger <k|h|\ell>a_\ell\right)\right]

Homework Equations



See (a)

The Attempt at a Solution



Just need some help getting started on this one, after that I'm good. What I do know is that when you do the commutator you cannot just lump the first term (a_k(t)) into the sum.. any hints on how to go about breaking this down? Halp!

Thanks

IHateMayonnaise
 
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To start with, the commutator is distributive (i.e. [A,B+C]=[A,B]+[A,C] ), so you take the sum out front. Also, like any inner product, \langle k|H|l\rangle will be a scalar, and so can be pulled outside the commutator...
 
Thanks for the reply!

So you said that because the commutator is distributive I can take the sum out front. Do you mean I can do this:

<br /> \left [ a_k(t),\left(\sum_{k,\ell}a_k^\dagger a_\ell\right)\right]=\sum_{k,\ell}&lt;k|h|\ell&gt; \left [ a_k(t),a_k^\dagger a_\ell\right]<br />
 
Yes, exactly...now keep going...simplify the commutator \left [ a_k(t),a_k^\dagger a_\ell\right]
 
gabbagabbahey said:
Yes, exactly...now keep going...simplify the commutator \left [ a_k(t),a_k^\dagger a_\ell\right]

I think I got it from here, thank you so much for your help!
 
Wait, what does the index k represent in the a_k(t)?...If it is not being summed over you should use a different letter for the dummy index in your sum.

\left [ a_k(t),\left(\sum_{n,\ell} a_n^\dagger a_\ell\right)\right]=\sum_{n,\ell} \left [ a_k(t),a_n^\dagger a_\ell\right]
 
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