Solve Trig Identity Problem: Eliminating θ from x=2+cscθ and y=1/4tanθ

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The discussion revolves around eliminating θ from the equations x=2+cscθ and y=1/4tanθ. Participants suggest starting by isolating cscθ and tanθ in terms of x and y, respectively. The key step involves using trigonometric identities to relate these functions, particularly the identity 1 + tan²θ = sec²θ. After manipulating the equations, one participant expresses clarity and gratitude for the guidance received. The conversation effectively highlights the process of transforming and solving trigonometric identities.
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I have been set an exercise from my textbook to do for homework but I am having some problems on one of the questions, I havn't encountered any of this type before and I am quite stumped.

"Eliminate \theta from equations x=2+\csc\theta and y=\frac{1}{4}\tan\theta"

So I am guessing I start off with x=y but then... :confused:
 
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start off by getting separate expressions for cscθ and tanθ from each of your two eqns.
Now you have to eliminate θ.
Can you do it from there ?
 
So for the first one would it goto,
2+\frac{1}{\sin\theta}=3+\cot\theta Then try eliminate theta from there?
 
not quite.
get two separate expressions. One for cscθ and one for tanθ.
Then find a trig identity involving the trig functions. You will have to manipulate the functions to get the identity.
 
I'm not sure what you are saying, get an expression for each equation so for the first one would become 2+\cot\theta and the second one \frac{1}{4}\csc\theta-\frac{1}{4} then put them equal to each other and try solve it?
I would appreciate it if you could show me the first step in tex form
 
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hang on a minute.
 
x = 2 + cscθ
y = ¼tanθ

cscθ = x - 2
tanθ = 4y

1 + tan²θ = sec²θ
 
Ahhh, it all becomes clear. Thanks a lot for the help It seems so easy now.
 
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