Solve Trig Limit Problem: lim (x->0) \frac{x - sinx}{x^{3}}

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Homework Statement



is there a way to solve

lim (x->0) \frac{x - sinx}{x^{3}}


using the fact that sinx / x = 1

or is it much more complicated.. I've tried to break it down into sinx/x everyway i can think of with no luck..
 
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Do you know l'Hopitals rule?

I am thinking of a way to do it with only sin(x)/x but can't come up with a good way immediately.
 
I am not familiar with l'hopitals theorem yet...
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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