- #1
Checkfate
- 149
- 0
Hello,
I am running into an error and I can't quite figure out what I am doing wrong.
The question is "solve 14\sin^{2}y-13=0 for y where 0<y<360.
So I factor it down to
14(sin(y)-\frac{\sqrt{182}}{14})(sin(y)+\frac{\sqrt{182}}{14})=0 (Thanks integral for showing me how to do this) :P
and thus get
y=74.5\deg or y=285.5\deg by using arcsine, but I am missing solutions somehow. I checked my answer with my calc and it's wrong, I am missing 105.5^ and 254.5^... how though? Adding the period length of 360^ does absolutely nothing. It's probably a small detail that I am overlooking, can someone point me in the right direction? Thanks again.
I am running into an error and I can't quite figure out what I am doing wrong.
The question is "solve 14\sin^{2}y-13=0 for y where 0<y<360.
So I factor it down to
14(sin(y)-\frac{\sqrt{182}}{14})(sin(y)+\frac{\sqrt{182}}{14})=0 (Thanks integral for showing me how to do this) :P
and thus get
y=74.5\deg or y=285.5\deg by using arcsine, but I am missing solutions somehow. I checked my answer with my calc and it's wrong, I am missing 105.5^ and 254.5^... how though? Adding the period length of 360^ does absolutely nothing. It's probably a small detail that I am overlooking, can someone point me in the right direction? Thanks again.
