Solve Wave Form Problem: Two Buoys 5m Apart, Wavelength 15m

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The problem involves two buoys 5 meters apart with a wave of 15 meters wavelength traveling between them. The left buoy's motion is described by the equation y=Acos(ωt), and the task is to determine the equation for the right buoy. The correct answer is option C, y = A cos (wt - 2π/3), which relates to the phase difference due to the distance between the buoys. The general wave equation y = A*cos(2πt/T - 2πx/λ) is referenced to clarify the relationship between time, distance, and wave properties. Understanding the role of x in the cosine function is crucial for solving such wave problems accurately.
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Homework Statement


Two buoys are floating in the sea, separated by 5 m. A wave with a wavelength of 15 m travels from left to right along the line between the buoys. The left-most buoy moves vertically up and down as described by the equation y=Acos(ωt). Which equation best describes the motion of the buoy on the right?

a) y = A cos (wt-pie/2)
b)y = A cos (wt + 90deg)
c) y = A cos (wt - 2pie/3)
d) y = A cos (wt- pie/4)
e) y = A cos (wt + pie/4)


Homework Equations





The Attempt at a Solution



I got my answer as C which is correct but I just guessed by finding the wavenumber and timsing it by 5.. i don't understand what x is in the cosine function for wave form exactly and i don't know how to solve this properly! cheers
 
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The general equation of a propagating wave is given by,
y = A*cos(2πt/Τ - 2πx/λ).
Here T is the period, λ is the wavelength and x is the distance where y is measured.
 
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