Solve x in tan(2x)=8cos(x)^2-cot(x) 0-90°

[rum2563]

Homework Statement

Solve for x.
tan(2x) = 8cos(x)^2 - cot(x) where x is between 0 to 90 degrees.

Homework Equations

tan(2x) = 2tan(x)/1-tan(x)^2
cot(x) = 1/tan(x)

The Attempt at a Solution

tan(2x) = 8cos(x)^2 - cot(x)
2tan(x)/1-tan(x)^2 + 1/tan(x) = 8cos(x)^2
(2tan(x)^2 + (1-tan(x)^2))/(tan(x)-tan(x)^3) = 8cos(x)^2

I am stuck at this point. Any help would be great since this is due tomorrow. Thanks.

 

[rocomath]

$$\tan{2x}=8\cos^{2}x-\cot{x}$$

correct? just making sure, I'm not really sure about your 2nd term.

 

[rum2563]

Yes, you are correct.