Solved: Dimensions of b/a in Pressure Equation

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The discussion focuses on determining the dimensions of the ratio b/a in the pressure equation P = b - t^2 / ax, where P represents pressure, t is time, and x is position. Participants emphasize the importance of dimensional homogeneity, noting that both b and the term -t^2/ax must share the same units as pressure for the equation to be valid. Clarification is sought on whether the equation implies a direct subtraction of the two components or if they are part of a single term. The conclusion drawn is that for the equation to hold, b must have dimensions that allow it to be combined with the term -t^2/ax, reinforcing the need for consistent units throughout the equation. The discussion ultimately highlights the necessity of ensuring all components of the equation are dimensionally compatible.
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Homework Statement



Assuming that Pressure (P) of a particle is given by

P = b - t^2 / ax

where t = time, x = position
Find the dimension of b/a.


Homework Equations







The Attempt at a Solution



Using dimensional homogenity, I know that b represents time interval.
 
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physics kiddy said:

Homework Statement



Assuming that Pressure (P) of a particle is given by

P = b - t^2 / ax

Is this (b-t2)/ax or b - (t2/ax)?

If it is the first, there is a subtraction of two quantities. Subtraction of what two quantities gives pressure? What does that tell you about b? and (t2/ax)?

If it's the second, what should be the dimension of b so that (t2/ax) can be subtracted from it? (apples and oranges? or, apples and apples? :wink:)
 
Assuming you have represented the formula correctly ...
Using dimensional homogenity, I know that b represents time interval.
I don't think so.
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your equation shows P comprising the sum of two components: b and (- t^2 / ax). Those two components must have identical units otherwise you couldn't add them, and what's more, they must have the same units as P.

P = b - t^2 / ax
 
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