Solved: Force Problem x-axis [SOLVED] Force Problem

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The discussion focuses on solving a physics problem involving two forces acting on a 3.00 kg object. The correct method to find the acceleration involves calculating the resultant force using vector addition, specifically by breaking down the forces into their x and y components. The final answer for the acceleration is determined to be 30.9 m/s² at an angle of 27.2 degrees above the positive x-axis. Several incorrect methods were attempted, including averaging forces and using the Pythagorean theorem incorrectly. Ultimately, the correct approach clarified the process of finding the resultant force and led to the correct answer.
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[SOLVED] Force Problem

Homework Statement


Only two forces act on an object (mass = 3.00 kg), as in the drawing (below). Find the magnitude and direction (relative to the x-axis) of the acceleration of the object.

http://img148.imageshack.us/img148/6302/imgfbic2.png

Homework Equations



F=ma

The Attempt at a Solution



F=ma
40N=(3.00kg)(a)
13.33m/s/s=a

Correct answer: 30.9m/s/s, 27.2 degrees above the +x axis.
 
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there are two forces acting on it so you would have to find the resultant force because you have to find the force net in order to use the F=ma equation. Finding the resultant by using vector addition method will give you the Force net and then you can plug in the mass to solve.
 
princesspriya said:
there are two forces acting on it so you would have to find the resultant force because you have to find the force net in order to use the F=ma equation. Finding the resultant by using vector addition method will give you the Force net and then you can plug in the mass to solve.

I understand what you're saying, but I'm confused. I thought I knew how to calculate the resultant vector, but the way I'm calculating it leads me to the wrong answer.

Can you please show me how to do it? I would greatly appreciate it. ;)
 
Show how you calculated the resultant.
 
Doc Al said:
Show how you calculated the resultant.

Okay.

I tried THREE ways:

1. I averaged the two vectors: .5(60N+40N) = 50N... Then I divided by 3 (since the weight is 3.00kg and F=ma). That equaled 16 and 2/3 m/s/s. Wrong.

2. I found the y component via Pythagorean theorem. It was √2000 = 44.7214N. Then I divided by 3 for the same reasons as #1. That equaled 14.97 m/s/s. Wrong.

3. I did R = r- r0. (R being the resultant vector I am trying to find.). R = 40N. I divided it by 3 and got 13 and 2/3 m/s/s. Wrong.
 
Why in the world would you (attempt to) take the average?

In any case, do this: Find the x & y components of each vector. Add up the x components: that will be the x component of the resultant. Do the same with y components to find the y component of the resultant.

You can then find the magnitude of the resultant via the Pythagorean theorem.
 
you have to split the 60 N into two different vector quantities since it has a horizontal and vertical magnitude. the 40 N only has a horizontal quantity. then you would add the horizontal component of 60 and 40 to get the total force in the x direction.
 
Doc Al said:
Why in the world would you (attempt to) take the average?

Haha, because none of the other ways I did it worked. :smile:

Doc Al said:
In any case, do this: Find the x & y components of each vector. Add up the x components: that will be the x component of the resultant. Do the same with y components to find the y component of the resultant.

You can then find the magnitude of the resultant via the Pythagorean theorem.

Thank you. I finally got the answer. :]

princesspriya said:
you have to split the 60 N into two different vector quantities since it has a horizontal and vertical magnitude. the 40 N only has a horizontal quantity. then you would add the horizontal component of 60 and 40 to get the total force in the x direction.

Thank you for your help too. :]
 
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