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**[SOLVED] Released Spring**

## Homework Statement

A piece of cheese with a mass of 1.35kg is placed on a vertical spring of negligible mass and a force constant k = 1600N/m that is compressed by a distance of 12.3cm .

When the spring is released, how high does the cheese rise from this initial position? (The cheese and the spring are not attached.)

## Homework Equations

U1 = Ugrav1 + Uel1

U2 = Ugrav2

v1 = 0

v2 = 0

K1 = 0

K2 = 0

K1 + U1 = K2 + U2

--> Ugrav1 + Uel1 = Ugrav2

y1 = -.123m

## The Attempt at a Solution

(1.35kg)(9.81m/s^2)(-.123m) + 1/2k(-.123m)^2 = (1.35kg)(9.81m/s^2)h

h = ((1.35kg)(9.81m/s^2)(-.123m) + 1/2(1600N/m)(-.123m)^2))/((1.35kg)(9.81m/s^s))

h = .80m

it's incorrect and I'm not sure what I'm doing wrong, at the bottom position where the spring is compressed the initial position should be less than 0 correct?

there's no velocity at the inital position and at the highest point there is no velocity or potential energy, only gravity should be acting on it correct? any help is greatly appreciated.