Solving a Basic Gravity Problem: How Fast Does a Tomato Fall from 100 Feet?

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A tomato dropped from 100 feet falls under the influence of gravity, which accelerates it at 32 ft/sec². The time taken to hit the ground can be calculated using the equation delta X = 1/2 at², resulting in a fall time of 2.5 seconds. However, there is confusion regarding the final speed calculation, as the initial attempt incorrectly applies the formula. The correct approach involves using the relationship between potential and kinetic energy, leading to the formula V² = 2gh for calculating the final velocity. This discussion emphasizes the need to review fundamental physics concepts related to free fall and energy conservation.
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I feel like an idiot asking this, it's review of a previous course as we start a new quarter, and I KNOW I used to be able to do this... but I don't remember how too. Time to review...

Homework Statement



A tomato is dropped from 100 feet above the ground. At what speed does it hit the ground?
How long does it take to fall the last 100 feet?

Homework Equations



Acceleration due to gravity is 32 ft/sec^2

The Attempt at a Solution



If I recall correctly, delta X = 1/2 at^2
100 = 1/2 32 T^2
200 = 32 T^2
6.25 = T^2
T = 2.5
Tomato hits ground after 2.5 seconds.
So now, plugging that in:
32 (2.5)^2 = 200... which is definitely not right.
 
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TG3 said:
I feel like an idiot asking this, it's review of a previous course as we start a new quarter, and I KNOW I used to be able to do this... but I don't remember how too. Time to review...

Homework Statement



A tomato is dropped from 100 feet above the ground. At what speed does it hit the ground?
How long does it take to fall the last 100 feet?

Homework Equations



Acceleration due to gravity is 32 ft/sec^2

The Attempt at a Solution



If I recall correctly, delta X = 1/2 at^2
100 = 1/2 32 T^2
200 = 32 T^2
6.25 = T^2
T = 2.5
Tomato hits ground after 2.5 seconds.
So now, plugging that in:
32 (2.5)^2 = 200... which is definitely not right.

Doing it your way, the last step would be V = a*t not t2

Otherwise you could take the Potential energy to kinetic energy relationship:

m*g*h = 1/2*m*V2

or

V2 = 2*g*h
 
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