Solving a DE for Water Leaking from a Tank

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Homework Help Overview

The discussion revolves around formulating a differential equation for the height of water in a tank leaking through a circular hole. The problem involves understanding the relationship between the volume of water leaving the tank and the height of the water, with specific parameters provided for the hole and gravitational acceleration.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants express confusion regarding the setup of the differential equation, particularly how the volume of water relates to the height and how to derive the rate of change of height from the volume flow rate. There are questions about the definitions of variables such as Ah and Aw, and their implications in the context of the problem.

Discussion Status

Some participants are seeking clarification on the relationships between the variables involved in the problem. There is an ongoing exploration of the mathematical expressions and their meanings, with no clear consensus reached yet.

Contextual Notes

Participants note potential ambiguities in the definitions of the areas involved and express uncertainty about how these areas relate to the height of water in the tank. The original poster's understanding of the problem setup is also questioned.

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Homework Statement



Suppose water is leaking from a tank through a circular hole of area Ah at its bottom. When water leaks through a hole, friction and contraction of the stream near the hole reduce the volume of water leaving the tank per second to

c.Ah.(2gh)^.5

, where c (0 < c < 1) is a empirical constant. Determine a differential equation for the height h of water at time t for the cubical tank shown. The radius of the hole is 2 in., and g = 32ft/s2

Homework Equations





The Attempt at a Solution



I am always confused in setting up a DE. Over here, the answer says that V= Aw(area of water). h . The next step written was that dh/dt = 1/Aw * dV/dt ... How does this make sense.. I am confused here. I understand that the "c.Ah.(2gh)^.5" given back in the question is dv/dt . But when you multiply it with 1/Aw, how do you get dh/dt ? Thanks for any help!
 
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ehabmozart said:

Homework Statement



Suppose water is leaking from a tank through a circular hole of area Ah at its bottom. When water leaks through a hole, friction and contraction of the stream near the hole reduce the volume of water leaving the tank per second to

c.Ah.(2gh)^.5

, where c (0 < c < 1) is a empirical constant. Determine a differential equation for the height h of water at time t for the cubical tank shown. The radius of the hole is 2 in., and g = 32ft/s2

Homework Equations





The Attempt at a Solution



I am always confused in setting up a DE. Over here, the answer says that V= Aw(area of water). h . The next step written was that dh/dt = 1/Aw * dV/dt ... How does this make sense.. I am confused here. I understand that the "c.Ah.(2gh)^.5" given back in the question is dv/dt . But when you multiply it with 1/Aw, how do you get dh/dt ? Thanks for any help!

The area of the hole is Ah? How can the hole's area depend on the height of water in the tank?
 
Ray Vickson said:
The area of the hole is Ah? How can the hole's area depend on the height of water in the tank?
I think the OP means this as Ah, not A * h. Also, I think Aw means Aw.

ehabmozart,
You can make what you write clearer by using the features available on this site. For example, to write exponents and subscripts, click the Go Advanced button below the input area, which causes the advanced menu to open across the top. One button is X2, which you can use to write exponents. Another button is X2, which you can use to write subscripts.
 
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ehabmozart said:
I am always confused in setting up a DE. Over here, the answer says that V= Aw(area of water). h . The next step written was that dh/dt = 1/Aw * dV/dt ... How does this make sense.. I am confused here. I understand that the "c.Ah.(2gh)^.5" given back in the question is dv/dt . But when you multiply it with 1/Aw, how do you get dh/dt ? Thanks for any help!

If you take the equation V = Aw * h and differentiate with respect to 't', what do you get?
 

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