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Solving a differential equation

  1. Jan 3, 2015 #1
    I want to solve Equation (1). w is a constant:
    \begin{eqnarray} \text{Equation (1): }\frac{dx}{dt}=1+x^2w^2\end{eqnarray}
    and I have been told that it is solved by (2):
    \begin{eqnarray} \text{Equation (2): }x(t)=\frac{Ax(0)+B}{Cx(0)+D}\end{eqnarray}

    Problem

    I believe them, but before I keep solving it I want to know how one concludes that (1) is solved by (2). In order to get (2), should I integrate something like (3)? Is it some kind of ansatz that I should have known? ...
    \begin{eqnarray} \text{Equation (3): }\frac{dx}{1+x^2w^2}=dt\end{eqnarray}
    I don't know what is it that I should be looking for. Could I get a clue?
    Thank you very much
     
  2. jcsd
  3. Jan 3, 2015 #2

    Mark44

    Staff: Mentor

    This doesn't make sense to me, assuming that I'm interpreting your notation correctly. x(0) is just a constant, so what you have on the right side in equation 2 is just a constant (doesn't depend on t). It couldn't possibly be a solution to your diff. equation. x(t) = K, so dx/dt = 0, and 1 + x2w2 ≥ 1.
    I would use a trig substitution to integrate what you have on the left side just above.
     
  4. Jan 3, 2015 #3

    ehild

    User Avatar
    Homework Helper
    Gold Member

    ##\int (\frac{1}{1+x^2}dx)=tan^{-1}(x) +C## , one of the basic integrals.

    Eq. (2) is true if A, B, C, D are functions of t.
     
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