Solving a Downward Motion Problem: Velocity of an Object

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To solve the problem of an object falling for 2.2 seconds over a distance of 12 meters, the initial velocity (vi) should be considered as 0 m/s, assuming it starts from rest. The final velocity (vf) can be calculated using the kinematic equations, specifically using the equation vf = vi + at, where 'a' is the acceleration due to gravity (approximately 9.81 m/s²). The total distance covered can also be verified using the equation d = vi*t + 0.5*a*t². Given the parameters, the calculations will yield the final velocity and confirm the distance fallen. Understanding these principles is essential for solving similar physics problems effectively.
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Hi I am new to Pf and I am a hs student

I just want to ask if i were given a problem:

a. what is the velocity of an object falling in 2.2s and the total distance is 12m.

what vi should i use is it 0 or the other velocity that i would get if i will solve for the whole downward motion problem?
 
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Welcome to PF. Could you please state the question exactly as it is give to you?
 
Its in my quiz so i don't have a copy =(

but as far as i could remember i could solve the vf of the falling object using vi as 0 because it is the vi when an object has reached its maximum height.

the problem is if the time is 2.2s considering 12m as the distance from the objects maximum height to the ground what is the velocity of the object and the distance on 2.2s =( sorry for an incomplete info =(
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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