Solving a Momentum Problem: Calculating Average Force and Impulse

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The discussion focuses on calculating the average force, impulse, and change in momentum for a racing car with a mass of 2500 kg that changes its velocity from 220 km/h south to 200 km/h north over 5 seconds. The average force is determined using the formula F_average = Δp / Δt, where Δp represents the change in momentum and Δt is the time interval. Participants seek clarification on how to find the average force applied in this scenario. The impulse of the force and the change in momentum are also key points of inquiry. Understanding these calculations is essential for analyzing the car's performance on the racing track.
rachael
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11 A racing car of mass 2500 kg changes its velocity from
220 km h–1 due south to 200 km h–1 due north in 5.0 s
on a racing track.

c What is the average force applied?
d What is the impulse of this force?
e What is the change in the momentum of the car?

what does part c means?
how do we find the average force applied?

thank you
 
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rachael said:
11 A racing car of mass 2500 kg changes its velocity from
220 km h–1 due south to 200 km h–1 due north in 5.0 s
on a racing track.

c What is the average force applied?
d What is the impulse of this force?
e What is the change in the momentum of the car?

what does part c means?
how do we find the average force applied?

thank you

The average force applied is F_{average} = {\Delta p \over \Delta t}, that is, the change of momentum over the time interval over which the change of momentum took place (this is the average form of F_x = { dp_x \over dt} for example).

Patrick
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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