Solving a Physics Magnification Problem with a 6cm Focal Length Magnifier

  • Thread starter Thread starter disk256
  • Start date Start date
  • Tags Tags
    Physics
AI Thread Summary
To solve the magnification problem, the magnifier with a 6 cm focal length must be positioned to create an image of 1 cm tall from a 1 mm tall object. The magnification formula m = -di/do is essential, but without a value for do, the calculation cannot proceed directly. By using the relationship hi/ho = di/do, one can express di in terms of do, ho, and hi. The required calculations involve substituting known values into the relevant formulas to determine the image distance. Assistance is needed to complete these calculations accurately.
disk256
Messages
2
Reaction score
0
1. The fine print in a contract that you want to read is 1 mm tall. You have a magnifier with a focal length of 6 cm. Where must you hold the magnifier so that the image appears to be 1 cm tall. Where is the image located



2. m= -di/do



3. using the equation given above i tried to use the equation hi/ho= di/do but no value for dO is given which means i can't use the equation


help would be appericiated
 
Physics news on Phys.org


Using this equation hi/ho= di/do find di in terms of do. ho and hi. Use the formula which related the f, do and di to get the required answer.
 

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

Find the location and length of the final image
Replies
2
Views
887
Graphically determining the focal length of a converging lens
Replies
4
Views
2K
Focal length of the eyepiece lens in a compound microscope
Replies
7
Views
1K
Finding Image Distance with a Converging Lens: Magnifying Glass Problem
Replies
12
Views
9K
What is the power of the lens in diopters?
Replies
3
Views
4K
What Focal Length Eyepiece Provides a -125 Magnification?
Replies
1
Views
2K
Calculating Image Height of Flower in Convex Mirror | Homework Question
Replies
3
Views
5K
Find Magnification of Reflecting Telescope
Replies
1
Views
2K
How to measure the magnification of a microscope in the lab
Replies
12
Views
3K
Optics Problem with a Double Lens System
Replies
1
Views
2K

Hot Threads

Recent Insights

Back
Top