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Solving a separable PDE with BC

  1. Nov 17, 2013 #1
    So I have a question in terms of interpreting the boundary conditions for a PDE. It is question 4 in the attached picture.

    My question is that usually when I have encountered BC problems I have been given that my boundary conditions equal a given value, in terms of the diffusion equation:

    U(0,t) = U(l,t) = 0,

    but as yuo can see they don't equate it to a constant. I know how to solve through for the PDE, but now I'm having trouble interpreting those BC in order to apply them to the ODEs I have obtained. Is there a constant I should assume that they equal?
     

    Attached Files:

  2. jcsd
  3. Nov 17, 2013 #2

    LCKurtz

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    Show us what equations you get when you let ##u(x,t) = X(x)T(t)## and apply it to the two boundary conditions. And please type it here instead of giving an uneditable image.
     
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