- #1
Jim4592
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Homework Statement
y''[x] = y'[x] + x
Homework Equations
We were taught two special types of second order diff. equations:
Type 1: Supposed to be when x is missing
v = y'[x]
v'[x] = y''[x]
Type 2: Supposed to be when y is missing
v = y'[x]
v v'[x] = y''[x]
The Attempt at a Solution
The answer key reads:
v'[x] - v = x
d/dx{e^-x v} = x e^-x
e^-x v = C1 * e^-x -x -1
v = C1 * e^x -x -1
y[x] = c2 - c1 * e^-x - (.5)x^2 - x
I don't understand why we used type 1 to solve this problem since x is clearly stated in the problem. I was hoping someone could explain, thanks.