Solving a trignometric equation.

  • Thread starter Thread starter Matriculator
  • Start date Start date
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 2K views
Matriculator
Messages
51
Reaction score
0

Homework Statement


Hello, I'm having some trouble with this: 3cosX+4sinX=2.


Homework Equations





The Attempt at a Solution


It's one of those problems where I've no idea of where to start. Could I possibly subtract 4sinX from both sides to get 3cosX=2-4sinX? And divide both sides by 3 to get cosX=(2-4sinX)/3? If this is right, it's from this point on that I'm confused. Thank you. The other problems were a bit simpler. 2 people, both Calculus tutors, couldn't help me on it.
 
Physics news on Phys.org
Matriculator said:

Homework Statement


Hello, I'm having some trouble with this: 3cosX+4sinX=2.


Homework Equations





The Attempt at a Solution


It's one of those problems where I've no idea of where to start. Could I possibly subtract 4sinX from both sides to get 3cosX=2-4sinX? And divide both sides by 3 to get cosX=(2-4sinX)/3? If this is right, it's from this point on that I'm confused. Thank you. The other problems were a bit simpler. 2 people, both Calculus tutors, couldn't help me on it.

Try to convert it in a form cosXsinθ+sinXcosθ=k which you can then rewrite to the form sin(θ+X)=k.
 
Pranav-Arora said:
Try to convert it in a form cosXsinθ+sinXcosθ=k which you can then rewrite to the form sin(θ+X)=k.

Oh, yep I see. Thank you. It's kind of late here, I'm going to bed, but I'll try it tomorrow morning. I remember my teacher showing us something like this.