Solving a trignometric equation.

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SUMMARY

The discussion focuses on solving the trigonometric equation 3cosX + 4sinX = 2. The initial approach involves rearranging the equation to isolate cosX, leading to the expression cosX = (2 - 4sinX)/3. A more effective method suggested is to convert the equation into the form cosXsinθ + sinXcosθ = k, which can then be rewritten as sin(θ + X) = k. This transformation simplifies the problem and provides a clearer path to the solution.

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Homework Statement


Hello, I'm having some trouble with this: 3cosX+4sinX=2.


Homework Equations





The Attempt at a Solution


It's one of those problems where I've no idea of where to start. Could I possibly subtract 4sinX from both sides to get 3cosX=2-4sinX? And divide both sides by 3 to get cosX=(2-4sinX)/3? If this is right, it's from this point on that I'm confused. Thank you. The other problems were a bit simpler. 2 people, both Calculus tutors, couldn't help me on it.
 
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Matriculator said:

Homework Statement


Hello, I'm having some trouble with this: 3cosX+4sinX=2.


Homework Equations





The Attempt at a Solution


It's one of those problems where I've no idea of where to start. Could I possibly subtract 4sinX from both sides to get 3cosX=2-4sinX? And divide both sides by 3 to get cosX=(2-4sinX)/3? If this is right, it's from this point on that I'm confused. Thank you. The other problems were a bit simpler. 2 people, both Calculus tutors, couldn't help me on it.

Try to convert it in a form cosXsinθ+sinXcosθ=k which you can then rewrite to the form sin(θ+X)=k.
 
Pranav-Arora said:
Try to convert it in a form cosXsinθ+sinXcosθ=k which you can then rewrite to the form sin(θ+X)=k.

Oh, yep I see. Thank you. It's kind of late here, I'm going to bed, but I'll try it tomorrow morning. I remember my teacher showing us something like this.
 

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